15p^2-19p-10=0

Solution for 15p^2-19p-10=0 equation:

15p^2-19p-10=0

a = 15; b = -19; c = -10;
Δ = b2-4ac
Δ = -192-4·15·(-10)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-31}{2*15}=\frac{-12}{30}
=-2/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+31}{2*15}=\frac{50}{30}
=1+2/3
$